F(x+4)=x^2+3x+9

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Solution for F(x+4)=x^2+3x+9 equation: 



(F+4)=F^2+3F+9

We move all terms to the left:

(F+4)-(F^2+3F+9)=0

We get rid of parentheses

-F^2+F-3F+4-9=0

We add all the numbers together, and all the variables

-1F^2-2F-5=0

a = -1; b = -2; c = -5;
Δ = b2-4ac
Δ = -22-4·(-1)·(-5)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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